Sunday, March 20, 2011

Chapter 5 Project: Determining the Number of Triangles in the Ambiguous Case (SSA): A Construction Exploration

Question 1:
Sin C is the same in both triangles in the ambiguous case because Sin A is the same as Sin C.

Question 2:
The thing that I discovered about the number of triangles you can make given SSA (two sides and an angle is that if BC is < or =" AB,">

Obtuse Triangle
a. BC > AB makes one triangle
b. BC = AB makes zero triangle
c. BC <>

Acute Triangle
a. AC > BC > h makes two triangles
b. BC > AC > h makes one triangle
c. BC = h makes one right triangle
d. BC <>

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